# Count Intersections of a list with a 2D-Array

```
import numpy as np
import pandas as pd
uniques = [[1, 3], [5, 9]]
df_values = [[2,5,7,1,3,6,0,5],
[1,3,4,5,6,7,8,9],
[3,9,9,9,9,9,9,9],
[1,3,4,5,6,7,8,9]]
df = pd.DataFrame([])
for combi in uniques:
a, b = combi[0], combi[1]
x = len([1 for row in df_values if a in row and b in row])
res = pd.DataFrame([a, b, x])
df = pd.concat([df, res], axis=0, ignore_index=True)
print(df)
```

Please note, that numpy.isin may come up with different results.

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